A few days ago
find the sideof a sqare with an area of 16z^2 – 24z + 9?
what numerical value must z be greater than for such a square to exist?
Top 1 Answers
A few days ago
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16z^2 – 24z + 9
16 x 9 = 144
-12 x -12 = 144 and -12 + -12 = -24
16z^2 -12z -12z + 9 “AC” method
-4z(-4z + 3) + 3(-4z +3) factor by GCF
(-4z + 3)(-4z + 3) = 0 Factor by grouping
z must be less than -4/3
if z were -4/3 then z would equal zero, thus no square
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