A few days ago
Anonymous

find the derivative of the given function y=2/x^2?

I know this is a easy one, but I forget how to do it. The text book shows easier examples and harder ones. I am studying for a quiz, I know the answer ( -4/x^3) but I would like to know the thought process. Thanks alot.

Top 3 Answers
A few days ago
gateach

Favorite Answer

Rewrite as 2x^-2

Multiply 2 by -2 and decrease the exponent by 1: -4x^-3

Move x^-3 to the denominator to make it positive: -4/x^3

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A few days ago
bente.nuebe
u = 2 (numerator)

v = x^2 (denominator)

du = 0 (derivative of numerator)

dv = 2x (derivative of denominator)

[v (du) – u (dv)] / v^2

= [x^2 (0) – 2 (2x)] / x^4

= [0 – 4x] / x^4

= -4x / x^4

factor it, you will get:

= x (-4) / x^4

cancel the x in the numerator and subtract 1 in the exponent of the denominator, you will get -4/x^3.

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A few days ago
lloyd_taggart11
if it’s y = 2/(x^2)

y’ = [(x^2)(0) – (2)(2x)]/(x^4)

y’ = (-4x)/(x^4) = -4/(x^3)

quotient rule

bottom times derivitive of top minus top times derivative of the bottom over the bottom squared

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