A few days ago
determining percentage composition?
table sugar sucrose has the chemical formula C sub 12, H sub 22 , O sub 11 .Determine the percentage composition by mass of surcose .( the molar mass of carbon ,C, is 12g/mol; of hydrogen ,H ,1 g/mol; and o oxygen, O,16 g/mol.)
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A few days ago
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When you have a molecular formula like C12H22O11, that tells you the “molar ratio” of the elements in the molecule. In other words, if you had 1 mole of table sugar, it would contain 12 moles of carbon, 22 moles of hydrogen, and 11 moles of oxygen. If you multiply each of those numbers by the molar mass, you’d get the total mass. For instance, if you have 11 moles of oxygen and oxygen’s mass is 16 g/mol, then you would have 16*11 = 176 g of oxygen within one mole of table sugar.
Once you know how much mass of each element you have, divide each element’s mass by the *total* mass of all the elements to get the percentage of the total mass that is made up of each individual element. For example, we said that one mole of table sugar has 176 g of oxygen. If you add the mass of oxygen, carbon, and nitrogen to get the total, pretend it’s 300 g. Then if you divide 176 by 300 (divide oxygen by total mass of all three elements), you’d get the percentage of the total mass that is made up of oxygen.
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