Could someone help me with a chem problem?

how many grams of Ca(OH)2 are needed to neutralize 25.0 mL of 0.100 M HNO3?

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A few days ago

³√carthagebrujah

Favorite Answer

Ca(OH)2 will liberate 2 OH when dissolved, so you need .5 moles of Ca(OH)2 per mole of HNO3. Knowing that, you can calculate your answer:

Calculations:

.025 L * .100 M HNO3 = .0025 mol HNO3.

.5 mol Ca(OH)2 / mol HNO3 * .0025 mol HNO3 = .00125 mol Ca(OH)2

.00125 mol Ca(OH)2 * 74.093 g/mol = 0.0926g Ca(OH)2 (solution)

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