A few days ago
Could someone help me with a chem problem?
how many grams of Ca(OH)2 are needed to neutralize 25.0 mL of 0.100 M HNO3?
Top 1 Answers
A few days ago
Favorite Answer
Ca(OH)2 will liberate 2 OH when dissolved, so you need .5 moles of Ca(OH)2 per mole of HNO3. Knowing that, you can calculate your answer:
Calculations:
.025 L * .100 M HNO3 = .0025 mol HNO3.
.5 mol Ca(OH)2 / mol HNO3 * .0025 mol HNO3 = .00125 mol Ca(OH)2
.00125 mol Ca(OH)2 * 74.093 g/mol = 0.0926g Ca(OH)2 (solution)
0
- Academic Writing
- Accounting
- Anthropology
- Article
- Blog
- Business
- Career
- Case Study
- Critical Thinking
- Culture
- Dissertation
- Education
- Education Questions
- Essay Tips
- Essay Writing
- Finance
- Free Essay Samples
- Free Essay Templates
- Free Essay Topics
- Health
- History
- Human Resources
- Law
- Literature
- Management
- Marketing
- Nursing
- other
- Politics
- Problem Solving
- Psychology
- Report
- Research Paper
- Review Writing
- Social Issues
- Speech Writing
- Term Paper
- Thesis Writing
- Writing Styles