Nope! Consecutive odd integers would be 3, 5, 7, 9, etc.

Start at the beginning.

x is the first, x + 2 is the second, and x + 4 is the third.

2(x + (x + 4)) = 21 + (x + 2)

2(2x + 4) = 23 + x

4x + 8 = 23 + x

4x = 15 + x

3x = 15

x = 5

x + 2 = 7

x + 4 = 9

Check:

2(5 + 9) = 21 + 7

2(14) = 28

28 = 28

a million. remedy for x. numerator x divided by denominator 4 destructive numerator 4 divided by denominator 5 equals numerator 19 divided by denominator 20 x/4 – 4/5 = 19/20 Multiply via by 20. 5x – sixteen = 19 5x = 35 x = 7 __________ 2. The sum of two consecutive integers is 121. What are the two integers? permit x and (x + a million) be the two consecutive integers. x + (x + a million) = 2x + a million = 121 2x = one hundred twenty x = 60 x + a million = sixty one the two consective integers are 60 and sixty one. ____________ 3. The sum of two consecutive integers is 109. What are the two integers? This concern works a similar way because of the fact the previous one. permit x and (x + a million) be the two consecutive integers. x + (x + a million) = 2x + a million = 109 2x = 108 x = fifty 4 x + a million = 55 the two consective integers are fifty 4 and 55.

I think by three consecutive integers they mean something like 3,5,7 or 7,9,11

So.

1st Integer = x

2nd Integer = x+2

3rd Integer = x+4

2(x+(x+4)) = 21+(x+2)

You should be able to complete it from there.

Your answer is right but the method is not. Take the integers to be (2x-1), 2x+1,2x+3. . . . and go about it in the same manner.