Chemistry help.?
The extraction of uranium uses the reaction of uranium tetrafluoride, UF₄ with magnesium.
UF₄+ 2Mg → 2MgF₂+ U.
Q1) Calculate the relative molecular mass of uranium tetrafluoride.
Q2) How many kilograms of uranium can be produced if 24 kilograms of magnesium is used?
Please show detailed working so that I would understand. I will vote for the best answer in 4 hours time.
Thank you very much.
Favorite Answer
M(U) = 238 g/mol , M(F) = 19 g/mol
so
M(UF₄)
= M(U) + 4*M(F)
= 238 + 4 * 19
= 314.0 g/mol
2)
M(Mg) = 24 g/mol for Mg
it’s actually 24.3 but based on the question it seems like your meant to approximate it as 24 for simplicity??
then
from the formula
2 moles of Mg makes 1 mole of U
so n(Mg) = 2n(U)………………..(1)
also you have
m(Mg) = 24000g of Mg
which, using n = m/M , is equivalent to
n(Mg) = m(Mg) / M(Mg) = 24000 / 24 = 1000 mol of Mg
so, using (1), you make
n(U) = (1/2)*n(Mg) = (1/2) *1000 = 500 mol of U
which, using n = m/M again, is equivalent to
m(U) = n(U) * M(U) = 500 * 238 = 119000g = 119kg of U
all of the terms in brackets after n,m and M are meant to be subscripts eg m(U) means mass of uranium etc
M for molar mass, n for number of moles
Also
How do you write the subscript of 4 in UF₄ ?
I’d really like to know
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