A few days ago
Check my answer please (Math)?
If a pro basketball player has a vertical leap of about 25 inches, what is his hang time? Use the hang-time function V = 48 T^2
Round your answer to the nearest tenth.
The answer I got was 173.21 seconds
Top 2 Answers
A few days ago
Favorite Answer
173.21 seconds would equal 2.886 minutes.
There’s no basketball player on earth
who can remain in the air for that long…
We’re looking for a hang time about one second, right?
(Try jumping about 2 feet high and time yourself).
V = 48T^2 or 48T^2 = V
48T^2 = 25
T^2 = 25 / 48
T^2 = 0.520833
sqrt(T^2) = sqrt(.520833)
T = 0.721688 seconds or about 3/4 of a second.
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* Always check your work *
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25 = 48 * (0.721688)^2 ?
25 = 48 * (0.520833) ?
25 = 25 <-- Checks! Good luck in your studies, ~ Mitch ~
0
A few days ago
Bravo! Correct!
BTW, You use calculator, rites? :l
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