A few days ago
Anonymous

Can someone please help me solve this really short chemistry calculation?

You have a 200.0 mL graduated cylinder containing 58.3 mL of water. A piece of metal with a density of 12.40 g/cm3 weighing 50.00 g is placed in the cylinder. What is the reading on the cylinder after the metal has been added?

Please, any sort of help is greatly appreciated. I tried it many different way. I know I have to use V=m/d.

Please help anytime you feel like it.

Top 1 Answers
A few days ago
Anonymous

Favorite Answer

The volume of the metal is:

(50.00gm) / (12.40gm/cm^3)

= 4.032cm^3

= 4.032ml.

The new reading on the cylinder is therefore:

58.3 + 4.032

= 62.3 ml. to nearest 0.1ml.

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