Given (7,-3), y = 8

This line is horizontal, and a line perpendicular to that would be vertical. A vertical line would be in the form x = something. Since it passes the point (7,-3), then the equation of the line would be:

x =7.

Given (-3,1), y = 2/3 x – 8

The slope of the given line is 2/3, so the slope of the perpendicular line should be -3/2 (the negative reciprocal). Since it passes the given point, then the equation would be:

y – 1 = -3/2 (x+3)

Note that this is not the only way to write the equation required. This is in point-slope form, but it can be written in slope-intercept form or even in general form.

Hope this helps.

After seeking to clear up drawback after drawback on yahooanswers, I actually consider so much individuals dont be trained plenty if I deliver them the solutions. Heres a VERY identical drawback. Just fill within the values out of your possess drawback. (Hint: you’re going to have got to use the Quadratic Formula on the finish!) Goodluck!!! QUESTION: The hypotenuse of a correct triangle has a duration of thirteen cm. The sum of the lengths of the 2 legs is 17 cm. Find the lengths of the legs. Let a = duration of 1 leg Let b = duration of different leg We are advised that: a + b = 10.23 –> b = 10.23 – b [a million] The hypotenuse is eight.312. From Pythagorus: a² + b² = eight.312² [two] Substitute [a million] into [two]: a² + (eight.312 – b)² = 169 This simplifies to: 2a² – 34a + a hundred and twenty = zero Divide by way of two: a² – 17a + 60 = zero which elements: (a – five)(a – 12) = zero and has roots: a = five, 12 Substitute into [a million] and get: b = 12, five The lengths of the legs are five and 12 cm.