Can somebody simplify some polynomials for me?
-2y(-2x^2y+3)
6ab(a^2+b^2)
(a^2+b^2+3)(ab-b)
(2ab+c)(2ab-c)
Also, im looking for a good tutorial for simplifing polynomials. We are doing some review on them in Geometry and I completely forgot it all from Algeba 1.
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So I think you’d just multiply out everything in there and then start collecting like terms. I’m not sure but I think you may have made an error in the first one (is that supposed to be 2x^2y, or 2x + 2y) so I’ll do the second one and the last one, and you can do the rest.
6ab(a^2 + b^2) = 6a^3b + 6ab^3.
(2ab + c)(2ab – c) = 4(a^2)(b^2) + 2abc – 2abc – c^2 = 4(a^2)(b^2) – c^2.
If that’s what you mean by simplify then I think that’s it.
As for a tutorial… I did a google search on “simplifying polynomials” and found this:
http://www.curriculum.org/tcf/teachers/projects/algebra/polynomialflash.adp
Check it out 🙂
Edit: To the person below me… “Maverick”, I’m not incorrect on the last one. How can I be? Your answer and mine are exactly the same. Please read again, thanks.
#1 are you telling me that the problem is -2y(-2x to power of 2y+3????
#2 person above was correct. You need only to multiply the 6ab by each of the entities within the parenthesis.
#3 you first need to multiply each of the entitites in the left paren, by each of the entities within the right paren and then combine like terms.
(a^3)b + a(b^3) +3ab – (a^2)b -b^3 -3b
since there are no like terms, there is nothing to combine and this is the final answer
#4 This is the classic FOIL (first, outer, inner, last) multiplication.
First = 4(a^2)(b^2)
Outer = -2abc
Inner = +2abc
Last = -c^2
since the inner and outer cancel each other out (added together they equal zero), the answer is
4(a^2)(b^2) – c^2
Note: I had to put the parenthesis around the a^2 to eliminate the confusion as in number 1
Good luck
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