Can anyone help me on my math homework?
2. Where A=1, B=2,…, Z=26, WE DEFINE A~B=2, A~B~C=6, A~C~C L=36, and A~B~C~…~Z=26!.. What set of three letters equal 1001 the ~operation?
3.In a non-leap year, what time on what day is exactly midyear?
4. Find the number of odd divisors of 7!
5.Three fair dice rolled. What is the probability that the product of the three outcomes i a prime number?
Favorite Answer
2. no clue
3. July 2, 12 pm
4. 2 (1 and 7)
5. 12:9 (not sure that’s right)
how I got it
1. Wrote out what the different endings of the game could be (X being lost)
XOO, XXO, XOX, XXX
In three of four of the games, he lost
3. 365 divided by 2 (182.5); looked at a calendar of this year and added the days of the months until I got to 182. It would be the next day at noon.
4. The only divisors of 7 are one and seven, and they’re both odd.
5. The prime numbers in 1-9 are 2, 3, 5, and 7. That’s four numbers, a chace of 4 in 9 that it’ll be prime on one roll. I times that by three for the three rolls, and since it olny had to be prime on one dice, the denominator stayed nine.
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