|x| = x if x >= 0, and |x| = -x if x < 0. So split the problem in two. 1) |r - 8| = r - 8 if r - 8 >= 0, that is, if r >= 8. In this case the equation looks like r – 8 = 2, thus r = 10. YOU MUST CHECK that the value agrees with the condition r >= 8: since 10 >= 8, this is OK.

2) |r – 8| = -r + 8 if r – 8 < 0, that is, if r < 8. In this case we get -r + 8 = 2, thus r = 6. Check that the value agrees with the condition: since 6 < 8 this is again OK. So there are two solutions: r = 6 and r = 10. Plug in both values into the original equation to see what's going on.

1.)Add 8 to both sides. The negative 8 and the positive 8 will cancel. R is equal to 10.(2 plus that 8)

2.) Put a negative sign in front of the equation and the answer

-[r-8]=-2 Everything inside changes

-r+8=-2 Subtract 8 on both sides

-8 -8

r=6

The answers are 10 and 6

l r-8 l = 2

There should be 2 answer for this, which means also 2 equation.

r-8 = 2 and r-8 = -2

(make the other side of the equal sign positive and negetive)

Answer: r = 10 and r = 6

I hope I helped!!!!!

the equation becomes r-8 =2

r=10