A few days ago
Calculus question?
Find dy/dx.
x+tan(xy)=0
Find dy/dx.
x+siny=xy
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A few days ago
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x+tan(xy)=0
Differentiating with respect to x:
1 + [ sec^2(xy)(x dy/dx + y) ] = 0
x sec^2(xy) dy/dx = -1 – y sec^2(xy)
dy/dx = [ -1 – y sec^2(xy) ] / [ x sec^2(xy) ].
x+siny=xy
1 + cos(y)dy/dx = x dy/dx + y
(cos(y) – x)dy/dx = y – 1
dy/dx = (y – 1) / (cos(y) – x).
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