A few days ago
Binomial Theorum? o.O?
How would you solve “Find the Coeffecient of x^-3 in the expansion of ((x-1)^3)(((1/x)+x)^6)”?? I dont know how to do 2 at the same time @-@
And then one step further, “Find the term ‘independant of x’ (What does this mean?) in the expansion of ((2-x)^3)(((1/3x)-x)^6)
Top 1 Answers
A few days ago
Favorite Answer
I assume you’ve been taught Pascal’s Triangle. I certainly hope so, since Yahoo won’t allow ASCII sketches. If not, do a websearch for it, as it will help immensely.
Using Pascal’s Triangle, you can easily expand the (x – 1)^3 and the ((1/x) + x)^6. Once you have those polynomials, you can pick out the terms that will give you the x^-3 terms, and Bob’s your Uncle.
In the second one, the “term independent of x” means the term that has no x-dependence. In other words, the constant term. For instance, in
x^2 – 2x + 3
the term independent of x is 3.
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