A few days ago
Emma

Answer 3 Math Questions Here and Get 10 points?

First to answer gets 10 points IT MUST BE ACCURATE

This is the question:

Insert brackets to make each equation true.

a) 15 ÷ 5 – 10 x 3(to the power of 2) = -27

b) 15 ÷ 5 – 10 x 3(to the power of 2) = -63

c) 15 ÷ 5 – 10 x 3(to the power of 2) = -87

Thanks a lot

Top 7 Answers
A few days ago
swanngranny

Favorite Answer

Gotta agree with the first guy, BUT….

let me help you out here, by explaining what YOU need to do to arrive at your accurate answer.

OK?

Seperate your problem into two parts:

1) 15 divided by 5….write down the answer.

2) 10 times 3 (squared)…write down the answer

3) take the first answer (3? 4? 5?)and

divide it by the second answer (30? 60? 90?)…

4) Bear in mind that ANY number, SQUARED, is the number TIMES ITSELF!

You can do it, kiddo!

PS…I hate math, too — but you GOTTA learn this stuff.

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A few days ago
meryl_shiningstar
a) [15/(5-10)] x 3(to the power of 2)

=[15/(-5)] x 9

=[-3] x 9

= -27

b) [(15/5)-10] x 3(to the power of 2)

=[3-10] x 9

= [-7] x 9

= -63

c) [15/5]-[10 x { 3 (to the power of 2)}]

=[15/5]-[10 x 9]

=3-90

=-87

There u go!!

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A few days ago
Anonymous
15 / 5 – 10 X 3x^a = b => 15 – 5 X( 10 X 3x^a )= 5b =>

– 5(10 X 3x^2) = 5b – 15 => – (10 X 3x^a) = b – 3 =>

x^2 = -(b – 3)/10X3 => x=squarerootof(-(b – 3)/10X3)

now you plug an appropiate “b” in there

You really need to be able to do these very simple things for yourself, they’re very very basic. If you’re not able to do even that you will have VERY low SAT scores and never get into college

next time ask this question in the math section

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A few days ago
I’m Just Me…
a)15÷(5-10) x (3 exponent 2)=-27

b)(15÷5)-10 x (3 exponent 2)=-63

c)(15÷5)- (10 x (3 exponent 2))= -87

1

A few days ago
Anonymous
I’m going to give them to you first with additional parentheses, to emphasize the necessary order of operations.

a) [15/(5 – 10)] * (3^2)

b) [(15/5) – 10] * (3^2)

c) (15/5) – (10*(3^2))

If we write them without the unnecessary parentheses, it would be

a) [15/(5-10)] * 3^2

b) (15/5 – 10) * 3^2

c) 15/5 – 10*3^2

Note that the last one is what you get if you just follow the standard order of operations.

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A few days ago
Anonymous
15 / 5 – 10 X 3x^a = b => 15 – 5 X( 10 X 3x^a )= 5b =>

– 5(10 X 3x^2) = 5b – 15 => – (10 X 3x^a) = b – 3 =>

x^2 = -(b – 3)/10X3 => x=squarerootof(-(b – 3)/10X3)

now you plug an appropiate “b” in there

You really need to be able to do these very simple things for yourself, they’re very very basic. If you’re not able to do even that you will have VERY low SAT scores and never get into college

next time ask this question in the math section

1

4 years ago
?
All you’re able to desire to do is get the variable (x, a, y, and so on) on my own on one element of the equivalent sign. a thank you to do it is to multiply, divide upload, subtract the comparable to the two element of the equation. to illustrate your 2nd situation: a/3 = 6… to get ‘a’ all by employing itself you multiply the two element of the equation by employing 3. So… a/3 * 3 = 6 * 3 —-> the three’s cancel out on the left leaving: a = 18 each and all the themes are solved in the comparable way.
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