Algerbra homework.. Help.. Find all real values of x such that f(x) =0. F(x)=16xsquared -9.?

so far I’m down to x squared = 9/16…I don’t even know if this is right.

Top 3 Answers

A few days ago

John V

Favorite Answer

I believe your eq’n is f(x) = 16x^2 – 9. Then we have the difference of squares: f(x) = (4x-3)(4x+3), so for f(x) = 0, we have x = 3/4, -3/4

A few days ago

Anonymous

16x^2 – 9 = 0

x^2 = 9/16

x = Â±â(9/16) = Â±(â9/â16) = Â±3/4 = -3/4 or 3/4

A few days ago

Anonymous

y=16x^2 – 9

0=16x^2 – 9

9=16x^2

9/16=x^2

+-sqrt(9/16) = x

+-(3/4) = x

Same result as above, just done a little differently.

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