A few days ago
algebra please help?
how do u go about this?
m^2+m+1=0
My work:
m^2+m=-1
m(m+m)=-1
m(2m)=-1
m=-1 m=-1/2
but i am suppose to get m=-1/2 plusminus (radical 3/2)i
thanks
Top 2 Answers
A few days ago
Favorite Answer
so the question asks for the value of m.
you can either use quadratic formula or solve by completing the square.
i prefer the second method. (completing the square)
m^2 + m + 1 = 0
subtract 1 for both sides
m^2 + m = -1
since the leading coefficient is already 1, add (b/2)^2 for both sides
m^2 + m + (1/2)^2 = -1 + (1/2)^2
simplify
m^2 + m + 1/4 = -3/4
factor
(m + 1/2)^2 = -3/4
take a square root
m + 1/2 = sqrt(-3/4)
m + 1/2 = +/- sqrt ( -1 * 3/4)
m + 1/2 = +/- sqrt(-1) * sqrt(3/4)
we know that sqrt(-1) = i
m + 1/2 = +/-sqrt(3/4)i
now subtract 1/2 for both sides
m = -1/2 +/- sqrt(3/4)i
or m = -1/2 +/- sqrt(3)i/2
0
A few days ago
Your second step doesn’t work…
m(m+m) = m^2 + m^2…
0
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