Not really sure what you want us to do with this problem

one half times the absolute value of x-3 times negative three halves (if i’m reading your question correctly):

first, multiply 1/2 and -3/2 and get -3/4

with out a value for x your answer would remain:

-3/4 times the absolute value of x-3

(if you have a value for x, plug it in, solve the x-3 equation first, take the absolute value, then multiply by -3/4)

In each and every case you’re putting y = 0 and fixing for y. In different words, in each and every case you’re finding for roots of a quadratic polynomial, in the different case for a shortcut that show you how to recognize related to the roots. If no longer the rest works for you, the Quadratic formula will preserve you. So will “winding up the sq.” (see under), that’s the belief in the back of the Quadratic formula besides. That mentioned: 4x^2 + 12x + 9 seems to equivalent (2x+3)^2. That has at maximum one root, and actual precisely one root, and that’s a rational one. Your trick clue could have been the actuality that 4 and 9 are the two appropriate squares. x^2 – 5x + 4 could be factored rather via the FOIL approach, and seems to have 2 rational roots (rather, they are the two integers). x^2 + x + one million = (x+one million/2)^2 + a valuable quantity. That has no genuine roots. (Why?) This “winding up the sq.” trick would be very useful.

i think its -1|x-3| but im not posative

sorry cant help still takin algebra I

IF ITS EASY DO IT YOURSELF!!!!!!!