A few days ago
Algebra Help pls?
The Problem Goes Like This: The total receipt for 1800 tickets were $1900. If students paid $1.50 per ticket and non students paid $2.50 per ticket, how many student tickets were sold??
I think the question is flawed… if you think you can solve pls tell me how.
tnx
Top 3 Answers
A few days ago
Favorite Answer
2.5 Y + 1.5 X = 1900
Y = 1800 – x
2.5 (1800 – x) + 1.5 (x) = 1900
4500 – 2.5 x +1.5 x = 1900
4500 – x = 1900
x = 2600 (tickets to students)
y = -800 (tickets to non-students)
The problem is flawed
0
A few days ago
Yes, the question is flawed. If the total receipts for 1800 tickets was only $1900.00, the average ticket price would be a little over $1.05 (1.0555555555 repeating), so no combination of $1.50 tickets and $2.50 tickets (totaling 1800 tickets in all) could possibly be $1900.00.
0
A few days ago
Let there be x students and y non-students
1.50x+2.50y=1900 — (1)
1.50x=1900-2.50y
x=(1900-2.50y)/1.50 — (2)
x+y=1800
y=1800-x
so (1) becomes
1.50x+2.50(1800-x)=1900
1.50x+4500-2.50x=1900
-x+4500=1900
-x=-2600
x=2600 (students)
y=1800-2600=-800 non-students (meaningless answer)
0
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