A few days ago
raindrop123

Algebra help…please?

I am confused about this question and the fact that it is using both supplementary and complementary angles; I don’t know how to make the step and put them together:

Question

Find the measure of an angle such that twice the measure of its complement is 16 degrees more than twice the difference between the measures of its supplement and its complement.

Any help would be great. Up to this point, the problems have been looking like this:

The angle’s measure is 81 degrees more than twice that of its supplement.

180-x = 2x+81 – subtract -81 from both sides

99 –x = 2x – add x to both sides

99 = 3x

x = 33

33*2=81 147 degrees

Top 2 Answers
A few days ago
don’t plagiarize

Favorite Answer

thats the answer i got, but i flunked calculus
0

A few days ago
Sydney S
2*[90-x]-16=[2*[[180-x]-[90-x]]]

180-2x-16=[2*[180-x-90+x]]

180-2x-16=[2*[90]]

180-2x-16=180

-2x-16=0

x=-8

Doesn’t seem right, but its what I get.

0