A few days ago
Add maths help!?
3^[(x^2)-5]- 9^(x-1)=0
I hope understand
Top 3 Answers
A few days ago
Favorite Answer
Your variables are all in the exponents, which implies you’re going to need logarithms. It would be easiest if the bases were the same, but they aren’t. However, one of your bases is 3 and the other is 9, which ought to suggest something since 9 = 3^2.
3^((x^2) – 5) – 9^(x – 1) = 0
3^((x^2) – 5) – 3^2(x – 1) = 0
3^((x^2) – 5) = 3^(2x – 2)
Take the log base 3 of both sides:
x^2 – 5 = 2x – 2
Now you have a quadratic, which should be easy to solve.
1
A few days ago
I think algebra gets really confusing aswell.. but with your sum, try and write it in expanded form and you may find it easier to make sense of!.. good luck
0
A few days ago
yeah…… square route of 62 i think
0
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