A few days ago
A line is formed passing through (6,-3) and parallel to 5x-6y=6?
i solved for it and this is what i got (parallel):
slope:5/6
point-slope form: y+3=5/6(x-6)
slope-intercept form: y=5/6x-12/6
standard form: 5/6x+-y=2
and for perpendicular:
slope: -6/5
point slope form:y+3=-6/5(x-6)
slope-intercept form: y=-6/5-51/5
standard form: -6/5x+y=-51/5
please check. i am a little rusty on this.
Top 1 Answers
A few days ago
Favorite Answer
5x-6y=6
y=(5/6)x-1
slope of parallel line is (5/6)
y+3=(5/6)(x-6)
y+3=(5/6)x – 5
y=(5/6)x-8 (slope-intercept, same slope different intercept) or
y+(5/6)x=-8 or
6y+5x=-48 (more standardized without fractions)
Since the question did not ask for perpendicular, I won’t retype, but you are correct in that the slope in the negative inverse.
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