A few days ago
A garden area is 30 ft long and 20 ft wide.?
A garden area is 30 ft long and 20 ft wide. A path of uniform width is set around the edge. If the remaining garden area is 400ft^2, what is the width of the path?
Top 4 Answers
A few days ago
Favorite Answer
width of path = x
(20-2x)(30-2x) = 400
600 – 40x – 60x + 4x^2 = 400
4x^2 -100x + 200 = 0
4(x^2 – 25x + 50) = 0
x^2 – 25x + 50 = 0
x = [25 +- sqrt(625 – 200) ] / 2
x = [25 +- sqrt(425) ] / 2
x = (25 +- 20.62)/2
x = 2.19 (22.81 is not feasible)
width of path is approximately 2.2 ft
which means the garden is approximately 15.6 ft by 25.6 ft
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5 years ago
30ft by 20 ft. is 600sq ft. If you subtract out the 400 sq ft. (the garden area) you are left with 200 sq ft. which should be the total area of the path. Since you know the lengths involved (30 by 20) you divide the remaining sq footage by that which would give you 4 feet wide.
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A few days ago
area of the garden(before the path installed): 30×20=600 ft^2
area of remaining garden area: 400 ft^2
Thus, area of the path is: 600-400=200 ft^2
the length of the path will be 20+20+30+30=100 ft
Thus the width of the path will be 200/100=2 ft.
The width of the path is 2 ft
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A few days ago
What is ^2?
I find no such symbol for a mathematical calculation
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