3c + 2c +4 = 13 – (2c – 5)

5c + 4 = 13 – (2c – 5)

subtract 13 from both sides

5c – 9 = -2c + 5

add 9 to both sides

5c = -2c + 14

add 2c to both sides

7c=14

c=2

then plug in the number to check your answer

3(2) + 2(2 + 2) = 14

13 – (2(2) – 5) = 14

14=14

so the answer is correct

2] For the 2(c+2) portion, multiply everything within the () by 2. You’ll end up with 2c+4.

3] Leave the 13 alone for now.

4] Because there’s a – in front of the (2c-5), you need to change the sign of everything inside the (). The 2c becomes -2c and the -5 becomes +5.

Now, when you rewrite the equation, you should have

3c + 2c + 4 = 13 – 2c + 5

On the left side of the =, you can combine the 3c+2c. On the right side of the =, you can combine the 13 and 5

When you do that, the equation will look like

5c + 4 = 18 – 2c

Next, you need to get all the c’s on one side of the equation. There is 5c on the left and -2c on the right. Add +2c to BOTH sides of the equation. You will get 7c on the left, and the -2c and 2c on the right will cancel each other out, leaving you with just the 18.

Now the equation looks like

7c + 4 = 18

Now, you want the c by itself on the left side, which means you have to get rid of that +4. Do this by subtracting 4 from both sides of the equation. The =4 and -4 on the left will cancel each other out. On the right, 18 – 4 = 14.

Now the equation looks like

7c = 14

Again, you have to get the c by itself, so you have to get rid of that 7. Do that by dividing both sides of the equation by 7.

The equation will look like

c = 2

And that’s your answer!

distribute the 2 to c and 2 and the -(1) to the 2c and -5

3c + 2c + 4 = 13 – 2c + 5

5c + 4 = 13 – 2c +5

add 2c to both sides and subtract 4 from both sides

7c = 13 + 5 – 4

7c = 14

c = 2