(1) 51,500

(2) 53,045

(3) 54,636.35

**(4) 56,275.44

2. Population in 2000 was 951,300 (subtract 1.4% from previous year’s total. All totals ended with decimal):

2001–937,981.80 (round figure=937,981)

2002–924,850.06 (round figure=924,850)

2003–911,902.16 (round figure=911,902)

2004–899,133.53 (round figure=899,134 because decimal was more than 1/2, so you round UP)

2005–886,547.64 (round UP to 886,548)

3. C is the answer–add 5% to previous year’s total:

start out at $225,000

(1) $236,250

(2) $248,062.50

(3) $260,465.62

(4) $273,488.90

(5) $287, 163.34

(6) $301,521.50

(7) $316,597.57

** (8) $332,427.44

4. B is the answer–add 3.75% to previous year’s total:

(1) $2593.75

(2) $2691.02

(3) $2791.93

(4) $2896.63

**(5) $3005.23 (or $3005 to nearest dollar)

5. C is the answer–subtract 2% from previous year’s total:

(1) $1225.00

(2) $1200.50

**(3) $1176.49 (or $1176 rounded to nearest dollar)

(Used ** to show which answer is right)

Annual rate of increase= 3%

Population in four years= ?

Start by taking 3% of 50,000

50,000 * .03= 1,500

Then add this amount to the whole 50,000

1,500+50,000= 51,500

This is the population in one year. Continue using the population of the previous year.

51,500 * .03= 1,545

1,545+51,500= 53,045=2 years population

53,045 * .03=1,591.35

1,591.35+53,045= 54,636.35=3 years population

54,636.35 * .03= 1,639.0905

1,639.0905+54,636.35= 56,275.4405=4 years population

The population of this city will be about 56,275 in four years.