When you say your nic., I’m assuming your nickname.

I’m guessing it has something to do with you being an extrovert on the Myers-Briggs Type Indicator.

Matt is correct. If x > 0 then ln(-x) = ln(x) + i*pi, so in the expression ln(-e) – ln(-1/e), the imaginary parts will cancel. EDIT: This assumes that we chose the principal branch of the natural logarithm. If we view the natural logarithm as a multivalued function then ksoileau’s answer is correct. RESPONSE: ln(1/x) = -ln(x) is valid when x > 0, but may fail for other values of x, if we choose a principal branch of the natural logarithm. For example, ln(1/(-1)) = ln(-1) = pi*i. The same issue arises with square roots of negative numbers. You may have seen the following “proof”: 1 = sqrt(1) = sqrt((-1)*(-1)) = sqrt(-1) * sqrt(-1) = i * i = -1

network interface card?

embti = bit(e) me?

LOL…