Suppose that a committee is needed to be formed of three students from a class of seven?

The name of each student in the class of seven is placed on a piece of paper and then three names are randomly drawn without replecing the drawn names. How many ways can the committee be determined?

Top 3 Answers

A few days ago

TurtleFromQuebec

Favorite Answer

The answer is 7C3, “7 choose 3” = 7!/(4!3!) = (7)(6)(5)/((3)(2)(1)) = 35. This is fine if you know those math terms. An easy way to see it directly is:

The first name can be chosen in 7 ways, the second in 6 ways (since one name is already chosen), and the third in 5 ways. But for a given set of three names, they can be chosen in 3(2)(1) = 6 different orders, using the same reasoning. So the total # of possibilities is 7(6)(5)/6.

A few days ago

xross14

Actually, the numerator should be n(n-1)…(n-r+1), and the denominator is r!

So, it’s (7)(6)(5)(4)/(4)(3)(2)(1) = 840 / 24 = 35.

So there are 35 ways for the committee to be determined.

A few days ago

Traci G

210

No doubt, as one of the four million odd Singaporeans, I am of the majority who only knows roughly what offsid

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Suppose that a committee is needed to be formed of three students from a class of seven?

Suppose that a committee is needed to be formed of three students from a class of seven?

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