A few days ago
Can anyone help me answer this question?
Joe has a total of $200 in his two pockets. He takes 1/4 of the money in his left pocket and puts it in his right pocket. He then takes $20 from his left pocket and puts it in his right pocket. If he now has an equal amount of money in each pocket, then how much money did he originally have in his left pocket?
Top 10 Answers
A few days ago
Favorite Answer
I solved this problem algebraically like this:
x+y=200 x=money in left pocket, y=money in right.
.25x+20+y=100, then solve for y and you get this.
y= -.25x+80, then substitute value for y in other equation.
x – .25x+80=200. combine like terms and solve
.75x+80=200, subtract 80 from both sides.
.75x=120, divide by.75
x=160
He had $160 in his left pocket.
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A few days ago
$160
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A few days ago
$160
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A few days ago
let x be the amount initially in left pocket
then x/4 is removed from it and then 20
so
x-x/4-20 equals half of amount ie 100
so x=320/4
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A few days ago
x = money he originally have in his left pocket
x-1/4x-20=100
3/4x=120
x=160
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A few days ago
hehe why would you put money in the other pocket?
lolz
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A few days ago
wow. looks easy but its not lmao. but don’t listen to me i’m getting a D+ in Pre-Algebra hahaha.
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A few days ago
i am guessing 100
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A few days ago
That’s not trivia. Do your own homework.
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A few days ago
ummmmmm joe has alot of money dude…..
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