A ladder is resting against a wall. The top of the ladder touches the wall at a height of 18 ft. Find the leng
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ladder = x+6
therfore the ladder is 30 feet
x squared + 8squared =(x+6)squared
b = 18 ft. (height)
c = 6+a (length)
the pythagorean theorem formula is c^2 = a^2 + b^2
so…
(6+a) ^ 2 = a^2 + 18^2
36 + 12a + a^2 = a^2 + 324
36 + 12a + a^2 – a^2 = 324… then a^2 will be cancelled out
36 + 12a = 324
12a = 324 – 36
12a = 288
a = 288 / 12
a = 24 << then this would be the DISTANCE OF THE LADDER FROM THE WALL. c = 6 + a c = 6 + 24 c = 30 << then this would be the LENGTH OF THE LADDER. ------------------------------ to check if it's correct, replace the values on the formula. c^2 = a^2 + b^2 so, it'll be.. 30^ 2 = 24^2 + 18^2 900 = 576 + 324 900 = 900 🙂
use the pythagorean theorem:
x=distance ladder is from wall
x+6=ladder’s length
18=height of wall
x^2+18^2=(x+6)^2
x^2+324=x^2+12x+36
reduce, you get: 288=12x
x=24–the distance ladder is from wall
now, plug it in: x+6
(24)+6=30
so, 30 feet is your answer!
Hmmm. Sorry, I can’t be bothered to work it out. My calculator is in the other room.
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