I calculated it based on the lessening error rate as the amount of balls produced increased. I divided 15 into 200, got 7.5 percent error rate, then divided 24 into 375, got 6.8 percent error rate, noted the increase in amount of balls produced, and saw that 625 would carry the same trend of decrease .07 percent (x 2), and so used 5.4 percent as the amount of defective balls that would be in that batch.

I have no idea how to show you the work – I’m in Intermediate Alg and haven’t had these yet. What class is this?

15 = x

200 625

then it is x multiplied by 200 and 625 multiplied by 15. the answer is: 47 balls