You’ve given us the function, there’s no domain.

An example of a domain is;

between x= -5 and x =5

or

-5< x > 5

The domain is basically the set of ‘input’ value sfor an equation. First of all, right the above function in y= form:

y = 5x^2 + 2x-1

Since the domain is the possible ‘x’ values, we need to find all of the values that will work for ‘x’. In this case, it should be ‘all real numbers’, or, in interval notation, (-infinity, infinity)

This is because any real number will work for ‘x’; but, if for example, instead of 5x squared it was the square root of 5x, the interval notation would be: [0, infinity) because you cannot have the square root of a negative number.

Hope that helped you out!!

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D = {x, x E R}

E= element of (when you write it it should be a curvy E)

R= real number system

this means x=+/- infinity

27x-1

you would square the 5x giving you 25x. then ad the 2x. giving the 27x-1.

all real #s