A few days ago
z scores again! 10 pts best answer!?
Reading test scores for Smithville had an average of 69.2 .
Nationally, the average was 60.3 with a standard deviation of 7.82. In Ms. Brown’s class, the average as 75.9.
a) what is the z score for Smithvilles average score?
b)what is the z score for Ms. Brown’s class average?
c)appromixately what percent of students in the country scored lower than Ms. Brown’s average?
z= x- xbar/s(standard dev.)
how do i compute the z core with out a specified amount of students??? Please Help!
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