A few days ago
dave h

write the expression. (2-3i)^2?

in the form a+bi where a and b are real numbers

Top 2 Answers
A few days ago
shuaib

Favorite Answer

(a+bi)^2=2-3i

this implies

=> a^2-b^2+2abi=2-3i

=> a^2-b^2=2 and 2ab=-3

solving two equations we get

a= -[2+(13^1/2)]/3;

b=[(13^1/2)-2] /2;

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A few days ago
greenwhitecollege
-5-12i
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