A few days ago
Way to do this problem besides guess & check?
Find the smallest number greater than 2000 that is divisible by 2, 3, 4, 5, and 6.
Is there any sort of equation?
Top 2 Answers
A few days ago
Favorite Answer
If it’s divisible by 6, it will also be divisible by 2 and 3. So, if you multiply 4x5x6 you get 120 which satisfies all factors. If you want it over 2000, multiply the 120 by 17 to get 2040. (I chose the 17 by dividing 2000 by 120 and rounding up.)
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A few days ago
Your number must be a multiple of the LCM of 2, 3, 4, 5, and 6, which is 60. So find the smallest number > 2000 that’s a multiple of 60. This would be 2040. (LCM = least common multiple = smallest number divisible by all of them)
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