Keeping this in mind, here is the answer to your question:

60 – 1,2,3,4,5,6,10,12,15,20,30,60

32 – 1,2,4,8,16,32

40 – 1,2,4,5,8,10,20,40

35 – 1,5,7,35

If it makes it any easier, it’s always best to start at the small numbers (1,2,etc…) and check if each is a factor. It also helps because once you know the small numbers, you can find many of the larger factors. Simply divide the starting number (the number that you are finding factors of) by that small factor to find the equivalent large factor. For example, I knew 4 was a factor of 60 and when I divided 60 by 4 I found that 15 was also a factor (60/4 = 15).

Some other hints:

1 goes into everything and 2 goes into even numbers. You can also figure out if a number is divisible by three by adding up the digits of the number and seeing if 3 goes into that. If it does then the number is divisible by 3. The same goes for 9.

Oh, and any number ending in 5 is divisible by 5 and any number ending in 0 is divisible by 10.

It just takes patience really.

Hints: If a number is even, it’s divisible by 2. If the sum of its digits is 3, it’s divisible by 3. If the sum of its digits is 9, it’s divisible by 9. If the number ends in a 5, it’s divisible by 5. If the number ends in a 0, it’s divisible by 5 and 10.

So:

60’s factors: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

60 = 2^2 * 3 * 5

32’s factors: 1, 2, 4, 8, 16, 32

32 = 2^5

40’s factors: 1, 2, 4, 10, 20, 40

40 = 2^3 * 5

35’s factors: 1, 5, 7, 35

35 = 5 * 7

Prime factors of 32 are: 1 x 2 x 2 x 2 x 2 x 2, all factors are:

1,2,4,8,16, and 32

Prime factors of 40 are: 1 x 2 x 2 X 2 x 5, all factors are: 1,2,4,5,8,10,20, and 40

Prime factors of 35 are: 1 x 5 x 7, all factors are: 1,5,7, and 35

1, 2, 4, 8, 16, 32= 32

1, 2, 4, 5, 8, 10, 20, 40= 40

1, 5, 7, 35= 35