A few days ago
use any method to solve 2x^2+2x+2=0?
use any method to solve 2x^2+2x+2=0?
Top 9 Answers
A few days ago
Favorite Answer
Agree with uri from helsinki. The equation has no real-valued solutions.
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A few days ago
2(-1^2) + 2(-1) + 2
= 2(1) + 2(-1) + 2
= 2 – 2 + 2
= 2
x != -1
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A few days ago
Do you realize the elements:
Element 1: 2xSquare
Element 2: 2x
Element 3: 2
Since it your homework, you solve it on your own. But you can get the answer by using the factorize. Or use the b-4ac formula.
Find the x… that sure no problem at all.
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A few days ago
2x^2+2x+2=0
divide through by 2
x^2+x+1=0
x^2+x=-1
x(x+1)=-1
x=-1,(x+1)=-1
x=-1,x=-1-1= -2
so x=-1 or -2
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A few days ago
Is it x=(-1)?
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A few days ago
You can always use the quadratic formula.
x = [ -2 +/- Root( 4 – 16) ] / 4
= [ -1 +/- i Root(3) ] / 2
i is square root of -1
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A few days ago
2x^2+2x+2=0
2(x^2+x+1)=0
2(x+1)(x+1)=0
X= -1
1
A few days ago
2*(x)^2+2*(x)+2=02*(x)^2+2*(x)+2=0 simplifies to 2*(x)^2+2*x+2=02*(x)^2+2*x+2=0
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A few days ago
You’re gonna obtain imaginery roots for this equation.
x= [-b+(b^2-4ac)^(1/2)]/(2a) or [-b-(b^2-4ac)^(1/2)]/(2a)
where a,b,c=2
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