A few days ago
campus_qt101

Two angles are supplementary. One is 60degrees more than twice the other. Fine the angles…??

Im in algebra 2 and this problem is working with solving problems using systems of equations…

Top 4 Answers
A few days ago
Srm2212

Favorite Answer

2x + 60 + x=180

3x+ 60 = 180

180-60= 120

3x=120

120/3= 40

x=40

<1= 140 <2= 40

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A few days ago
Lone Wolf
Supplementary angles are two angles whose sum is 180 degrees. Thus, we have the equation

x+y=180

and one is 60 degrees more than twice the other, so

x=60+2y (doesn’t matter which one you choose as x or y)

Now, we have two equation to work with (that’s what we want)

x+y=180

x=60+2y

As you can see that the second equation has the value of x because x=60+2y

Then we can use substitution to find the value of y

Change the “x” in the first equation into 60+2y, we have

60+2y+y=180

60+3y=180

3y=180-60

3y=120

===>y=120/3

===>y=40

Now we have to find the value of “x”, use the second equation and plug in the 40

x=60+2(40)

x=60+80

x=140

The answer is

x=140 degrees

y=40 degrees

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A few days ago
Twiggy
If they are supplementary, then they add up to 180 deg.

Let one angle be x, so the other, which is 60deg more than

twice the other, will be 2x + 60, so,

x + 2x + 60 = 180, so,

3x + 60 =180,so,

3x = 120, so,

x = 40, and the Angles are 40 deg, and 2×40+60, =140deg.

Hope this helps, Twiggy.

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A few days ago
D.B.O.
let’s name a the first and b the second angle.

a=60+2b

a+b=180

so we have:

a+b=180

60+2b+b=180

60+3b=180

3b=180-60

3b=120

b=120/3

b=40

did you understand?

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