Two angles are supplementary. One is 60degrees more than twice the other. Fine the angles…??
Favorite Answer
3x+ 60 = 180
180-60= 120
3x=120
120/3= 40
x=40
<1= 140 <2= 40
x+y=180
and one is 60 degrees more than twice the other, so
x=60+2y (doesn’t matter which one you choose as x or y)
Now, we have two equation to work with (that’s what we want)
x+y=180
x=60+2y
As you can see that the second equation has the value of x because x=60+2y
Then we can use substitution to find the value of y
Change the “x” in the first equation into 60+2y, we have
60+2y+y=180
60+3y=180
3y=180-60
3y=120
===>y=120/3
===>y=40
Now we have to find the value of “x”, use the second equation and plug in the 40
x=60+2(40)
x=60+80
x=140
The answer is
x=140 degrees
y=40 degrees
Let one angle be x, so the other, which is 60deg more than
twice the other, will be 2x + 60, so,
x + 2x + 60 = 180, so,
3x + 60 =180,so,
3x = 120, so,
x = 40, and the Angles are 40 deg, and 2×40+60, =140deg.
Hope this helps, Twiggy.
a=60+2b
a+b=180
so we have:
a+b=180
60+2b+b=180
60+3b=180
3b=180-60
3b=120
b=120/3
b=40
did you understand?
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