Although you can simply do this using a calculator, you can use calculus as well.

y=-0.042x^2+5x can be read as function f(x)=-0.042x^2+5x

The first derivative will tell you minimum and maximums on the graph when you set it equal to 0. This we find f'(x), the first derivative, and set it equal to 0.

f'(x)=-.084x + 5 = 0

x = 59.5

To check if its a max or a min, pick a # < 59.5 and a # > 59.5. I am using 55 and 60 for convenience.

f'(55) = .38, a positive #

f'(60) = -.04, a negative #

The change in signs from positive to negative shows that x=59.5 is a maximum point.

Thus, we plug it into f(x) to find the max height reached.

f(59.5) = 148.8 yards

To find the ball hit the gound, you would find where f(x) = 0.

f(x)=-0.042x^2+5x = 0

x (-.042x + 5) = 0

x= 0 or 119

x=0 is essentially where the ball was hit, and 119 represents where the ball lands,

so x = 119 = where the ball lands on the ground