The length of a rectangle is 2 cm more than 5 times its width. Find the dimension of the rectangle.?

The length of a rectangle is 2 cm more than 5 times its width. If the area of the rectangle is 65 cm^2, find the dimensions of the rectangle to the nearest thousandth.

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A few days ago

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The length of a rectangle is 2 cm more than 5 times its width.

L=5w+2

A=Lw=65 cm^2

Replace L with 5w+2 in the second formula. You will get:

(5w+2)w=65

5w^2+2w-65=0

Solve this quadratic equation

w=[-2+sqrt(4+1300)]/10=(-2+36.11 )/10=34.11/10=3.411 cm

L=5w+2=5(3.411)+2=19.055 cm

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The length of a rectangle is 2 cm more than 5 times its width. Find the dimension of the rectangle.?

The length of a rectangle is 2 cm more than 5 times its width. Find the dimension of the rectangle.?

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