A few days ago

kaylee826

Solve |x – 4| < 3.?

Solve |x – 4| < 3. -7 < x < -1 1 < x < 7 1 > x > 7

-7 > x > -1

Top 7 Answers

A few days ago

mara_malaluan

Favorite Answer

Case I

x-4<3 x<3+4 x<7 Case II x-4<-3 x<-3+4 x<1 I think the answer is 1

A few days ago

The correct way to do this is to square both sides

{|x-4|}^2 < 9 But (|a|)^2 = a^2 so (x-4)^2 - 3^2 <0 or (x-4+3)(x-4-3) <0 [using a^2-b^2 = (a+b)(a-b)] or, (x-1)(x-7) <0 so, either x-1<0 AND x-7>0 which implies

x<1 AND x>7 ….no solution in this interval

or, (x-1)>0 AND (x-7)<0 which implies x>1 and x<7 ... so the solution set is 1

A few days ago

Anonymous

none are true

is there a choice for -7 x 1

or -1 x 7

all the answers you listed = 7 which is > than 4

A few days ago

Anonymous

A few days ago

scide i

lx-4l<3 add 4 to both sides lxl>7

anwser lxl>7

any number greater than 7

any number smaller than -7

A few days ago

lawandasan

{0,1,-1,2,-2,3,-3,4,-4,5,-5,6,-6}

|x – 4| < 3 First, add 4 to both sides + 4 +4 Simplify |x| < 7 Find all numbers that make this statement true {0,1,-1,2,-2,3,-3,4,-4,5,-5,6,-6}

A few days ago

PIOLO

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