Solve |x – 4| < 3.?
-7 > x > -1
Favorite Answer
x-4<3
x<3+4
x<7
Case II
x-4<-3
x<-3+4
x<1
I think the answer is 1
{|x-4|}^2 < 9 But (|a|)^2 = a^2 so (x-4)^2 - 3^2 <0 or (x-4+3)(x-4-3) <0 [using a^2-b^2 = (a+b)(a-b)] or, (x-1)(x-7) <0 so, either x-1<0 AND x-7>0 which implies
x<1 AND x>7 ….no solution in this interval
or, (x-1)>0 AND (x-7)<0 which implies
x>1 and x<7 ...
so the solution set is 1
is there a choice for -7 x 1
or -1 x 7
all the answers you listed = 7 which is > than 4
anwser lxl>7
any number greater than 7
any number smaller than -7
|x – 4| < 3 First, add 4 to both sides + 4 +4 Simplify |x| < 7 Find all numbers that make this statement true {0,1,-1,2,-2,3,-3,4,-4,5,-5,6,-6}
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