A few days ago
Anonymous

solve this problem a person weight 0.9 kN rides in a neleveator that has a downward acceleration of 1.1 m/s^2?

what is the magnitude of the force of the elevator floor on the person

Top 1 Answers
A few days ago
Anonymous

Favorite Answer

F = m * a

convert 0.9 kN to mass

0.9 * 1000 = 900 N

900 N / 9.8 m/s^3 = 91.84

Multiply mass times gravity – downward acceleration

F = 91.84 * (9.8 – 1.1) = 798 N

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