You then expand the brackets

x^2 – 4x + 4 = 25

Take 25 from both sides

x^2 – 4x -21 = 0

Solve the quadratic on the left side

The answer is x = 3 or 7

Sorry i couldnt explain it all but its hard on the computer. Good luck

[x-2]^2 = 25, so,

[x-2][x-2] = 25, so,

x^2-2x-2x+4 = 25, so

x^2-4x+4 = 25, so

x^2-4x-21 = 0, Now factorise the left hand side,

[x-7][x+3] = 0, so

x-7 = 0, OR x+3 = 0, so

x = 7, OR x= -3. Hope this helps, Twiggy.

Start by taking the square root of each side of the equation. You’ll end up with: x-2=5.

You can perform any simple operation…as long as it’s performed on both sides of the equation.

Hint: There’s also a negative value that will work. I’ll leave this for you to figure out.

then subtract 4 from both sides and u get x^2 -4x=21

subtract 21 from both sides and u get x^2 -4x -21

then solve an du get (x+3)(x-7)the two answers are -3 and 7