Since 3/4 and 5/4’s are both fractions with “4” in the denominator… you could ignore the “4” in the denominators and first distribute the 3 to both terms in the first set of ( )’s…. then distribue the 5 to both terms in the 2nd set of ( )’s…. combine all your “like” terms… and then lastly divide all you final terms by “4”…. to account for the “4” in the denominator that I told you that you could ignore in the beginning…

Here… let me show you what I mean…

You say that your problem is (3/4)(2h+9) – (5/4)(h-1)… right?

Okay…. ignore the denominators … that is, the “4”s

So you will just have 3(2h+9) – 5(h-1) now… right?

Okay… so…

3(2h+9) – 5(h-1)

= (3)(2h) + (3)(9) – [(5)(h) + (5)(-1)]

= 6h + 27 – (5h – 5)

= 6h + 27 – 5h + 5

= h + 32

But now divide all the terms by “4”…

(h + 32)/4 = h/4 + 8 …. or you could have just said (1/4)(h+32)

know your order of operations.

first multiple the fractions with their coefficient (the terms in parentheses).

(3/4*2h)+(3/4*9)-(5/4*h)-(5/4 * 1)

work that out and group like terms (h and then the regular numbers)