A few days ago
manhattanbrat

solve for the system of eqns 2x+y=30 and y=-2x-1 show steps?

solve for the system of eqns 2x+y=30 and y=-2x-1 show steps?

Top 2 Answers
A few days ago
gervin_tan

Favorite Answer

There are two general approaches to solving a system of equations.One is by using the process of elimination, and the other is by using the process of substition. Either way, you simplify the system of two equations with two unknowns to just one equation with one unknown.

a) SUBSTITUTION:

Since y = -2x-1, we can substitute -2x-1 for y in the first equation.

2x + (-2x-1) = 30

2x-2x-1=30

-1=30

Since -1 is NOT equal to 30, then there is no solution to the given system of equations. This means that there is no value for x and y that will make both equations simultaneously true.

b) ELIMINATION

We can multiply both sides of the equation y=-2x-1 by -1. We get -y =2x+1.

Then we add the two equations (actually, add the two left sides and the two right sides).

(2x+y) + (-y) = 30 + (2x + 1)

2x + y – y = 30 + 2x + 1

2x = 31 + 2x

2x-2x = 31

0 = 31

Again, since 0 is NOT equal to 31, we come up with the same conclusion that there is no solution to the system of equations.

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4 years ago
Erika
Does there must be in basic terms 5 steps? that’s what I have been given: 10(2x-3)-2(3x+4)=4(x-a million)+sixteen {unique question} 20x-30-6x-8=4x-4+sixteen {use distributive regulation to do away with the brackets-multiply in> 10 situations 2x equals 20x and 10 situations 3 equals 30 etc.} 14x-38=4x+12 {combine like words> 20x-6x=14x etc.} 10x-38=12 {pass the x’s to a minimum of one side} 10x=38+12 {isolate the x}10x+50 {divide via 10 on the two aspects to isolate x some greater} x=5 desire this helped!!! 😀
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