A few days ago
solve and explain?
The length of a rectangle is 2 in more then twice its width. If the perimeter of the rectangle is 34 in, find the demensions of the rectangle.
Top 4 Answers
A few days ago
Favorite Answer
Not doing your homework for you. Good luck.
0
A few days ago
Set it up as a system of equations
l= 2+ 2w
2l + 2w = 34
2w = 34- 2l
l = 2 + 34-2l
3l = 36
l= 12
w = 10
When your faced with this kind of problem always start out by listing everything you know and then try to manipulate one of the functions to see if you can get it in a form you can plug into another function
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A few days ago
L=2+2w
P=2L+2w=34
2(2+2w)+(2w)=34
4+4w+2w=34
4+6w=34
6w=30
w=5 inches
L=2+2(5)=12 inches
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A few days ago
is this for your homework…if so you need to ask for help on how to do it instead of asking for the answer. But thank you as a future teacher I know to check resources like these out… and good luck i’m sure someone will give you the answer
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