2p+5a=3.30

multply 2nd equation by 3

6p+15a=9.90

subtract

12a=6

a=.50

Now substitute a in the first equation to get p.

6p+3*.50 = 3.90

6p=3.90-1.50

6p=2.40

p=.40

*

6p + 3a = 3.9

2p + 5a = 3.3

Multiple equation 2 by 3 to get 6p + 15a = 9.9

Subtract the two equations

6p + 15 a = 9.9

6p + 3a = 3.9

12a = 6, a = .5 substitute into either equation

6p + 1.5 = 3.9

6p = 3.9-1.5 = 2.4

p = .4 or 40 cents

verify

6 (.40) + 3(.5) = 2.4 + 1.5 = 3.9

2 (.40) + 5 (.50) = .80 + 2.50 = $3.30

6p + 3a = 3.90

2p + 5a = 3.30

Use whatever method you want to solve for p and a. Then add p and a together to get the cost of one of each.

Let equation 2) read 2p+5a=3.30

using simultaneous equation to solve

equation 1) 6p=3.90-3a

p=? etc

then place p in equation 2) to get cost of then do b.

hey can’t do everything for you rite

actually i’m surprised i remember this stuff

get one variable alone….6p+3a=3.90

You may divide the whole equation by 3

2p+a=1.30

a=1.30-2p

Substitute the results for a in the second equation

2p+5(1.30-2p)=3.30

2p+6.50-10p=3.30

-8p+6.50=3.30

-8p= -3.20

8p=.3.20

p=.40

Use the price of a pear to figure out the cost of an apple

6p+5a=3.90

6(.40)+5a=3.90

2.40+5a=3.90

5a=3.90-2.40

5a=1.50

a=.30

Check your work when done by substuting the values back into the oriignal equations