x^2 + 2x = -5 (add 5 to both sides)

x^2 + 2x + 5 = -5 + 5 = 0

x^2 + 2x + 5 = 0 (now you can use the quadratic formula to solve)

-b +/- (b^2 – 4ac)^1/2

—————————–

2a

(-2 +/- (4 – 4*1*5)^1/2) / 2*1

-1 +/- (-16)^1/2 / 2

-1 +/- 4i/2

x = -1 – 2i and -1 + 2i

I suspect there is a typo in your original equation.

Slope-intercept form: y = mx + b, the place m is the slope and b is the y-intercept a million.) The slope is 4, so which you already be responsive to the equation so a techniques is y = 4x + b. Now substitute the element (a million, -2) for x and y into the equation so which you would be able to remedy for b: y = 4x + b (substitute a million for x and -2 for y) -2 = 4(a million) + b -2 = 4 + b -6 = b answer: y = 4x – 6 2.) lower back, the slope is 3, so its equation so a techniques is y = 3x + b. remedy for b by employing substituting the element (5, -3) for x and y into the equation: y = 3x + b -3 = 3(5) + b -3 = 15 + b -18 = b answer: y = 3x – 18 3.) comparable element… y = -3x + b 0 = -3(-3) + b 0 = 9 + b -9 = b answer: y = -3x – 9 4.) This time the slope is undefined, which ability the line is vertical. whilst the slope is undefined, the equation of the line is immediately x = ?. The x-coordinate of the element (7, 8) is 7, so the equation of the line is merely x = 7. answer: x = 7

x^2 + 2x = -5 change to a quadtratic formula by adding 5 to both sides to get

x^2 + 2x + 5 = 0 ax^2 +bx + c

use the quadratic formula: (sqrt is square root)

x = [-b+/-sqrt(b^2-4ac)]/2a (yes, it looks really strange here)

for your quad, a=1 b=2 and c=5 plug in and solve….

(+/- is plus-or-minus symbol)

x =

-2 +/- sqrt(2^2 – 4*1*5) all divided by 2*1

= -2 +/- sqrt(4 – 20) all divided by 2

= -2 +/- sqrt(-16) / 2

>>>square root of 16 = 4, square root of negative is the imaginary number i >>> if you haven’t done complex numbers, then the answer is no solution….

= -2 +/- 4i /2 = -2/2 +/- 4i/2

at this point my memory is fuzzy, but I think the answer becomes -1 +/- 2i

x^2 + 2x=-5

x^2 +2x +5=0

Seems impossible. Even if x is negative, once you square it, it’ll be a high positive, & 2x that won’t be big enough to get down to a negative number.

answer is not 3…

x^2 + 2x = -5

implies x^2 + 2x + 5 =0

x= ( -2 + sqroot(2*2 – 4*1*5) ) /2 or

( -2 – sqroot(2*2 – 4*1*5) ) /2

x = -1 + 2i , -1 -2i

I don’t remember. At first I thought it was easy….but……NO. I haven’t taken math since junior year. And that was precalc. So I have NOOOO idea.

use the quadratic formula

if you don’t remember/know it it’s [-b +- sqrt (b^2 -4ac)]/2a

use the quadratric formula (remember that one….ick 🙂

a=1

b=2

c=5

That should give you the answer.