1/6×1/2 so the probability, is that once out of every twelve occasions you roll the dice and flip the coin getting a two and a tail

1/12

the probability of getting a tail on the coin is 1/2 for the same reason therefore the probability of getting both is 1 in 12

the probability of getting either (the or statement) is equal to the probability of the die plus the probability of the coin

but because the events are not mutually exclusive (they can both happen at the same time) we have to subtract the probability of both happening which is 1/12 from the probability of the coin plus the probability of the die

so 1/6+1/2-1/12

which is 7/12

if you dont believe me write out all the possibilities there are 12 1:H 2:H…. etc 1:T 2:T etc.

you will find that 7 are either tails or have a 2 and 1 has both