A few days ago
Michael n

Please tell me how to do this, NOT the answer?

Write the equation for the line perpendicular to

4x – 7y = 7 and passes through the point (-4, -7).

What are the steps?

Top 3 Answers
A few days ago
Anonymous

Favorite Answer

first change the equation to look like a regular y=mx+b line equation.

4x-7y=7

y=4/7x-1

perpendicular lines have a slope that is the negative reciprocal of a given line.

So: y=-7/4x + b

is your new line. Now plug in -4 for x and -7 for y and solve for b.

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A few days ago
Anonymous
1. Make y the subject of the equation.

2.Find the gradient of the line/equation.

3. The rule of equations of perpendicular lines states that if two perpendicular lines have gradients m1 and m2 then,

m1 = -1/m2 or m1m2 = -1

4. Use the point-graidient formula y – y1 / x-x1 = m where in your case, y1 = -7 and x1 = -4.

5. Solve

Hope this helps, i can work it out for you if you want!!

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A few days ago
kat
4x-7y=7

-4x -4x

————–

-7y=-4x+7

y=4/7x-1

slope: neg reciprical is perpendicular so…

4/7—-> -7/4

y=mx+b

-7=(-7/4)(-4)+b

-7=7/16+b

-7 7/16=b

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